Matematika

Pertanyaan

log 11/55+log490/297-2log7/9-log2

1 Jawaban

  • log (11 / 55) + log (490 / 297) - 2 log (7 / 9) - log 2 

    = log (1/5) + log 490 - log 297 - 2 (log 7 - log 9) - log 2 
    = log 1 - log 5 + log (7² × 5 × 2) - log (9 × 3 × 11) - 2log 7 + 2log 9 - log 2 
    = 0 - log 5 + log 7² + log 5 + log 2 - log 9 - log 3 - log 11 - log 7² + 2log 9 - log 2 
    = log 9 - log 3 - log 11 
    = 2 log 3 - log 3 - log 11 
    = log 3 - log 11 
    = log (3/11)

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