4log 64-5log1/25+6log1 Tolong bantu ya sama caranya

[tex]4 log(64) - 5 log( \frac{1}{25} ) + 6 log(1) \\ = 4 log({4}^{3} ) - 5 log( {5}^{ - 2} ) + 6 log( {6}^{0} ) \\ = 3 .4 log(4) - ( -2). 5 log(5) + 0.6 log(6) \\ = 3 - ( -2) + 0 \\ = 5[/tex]
Ket :
[tex]a log( {b}^{n} ) = n.a log(b) \\ 4 log( {4}^{3} ) = 3.4 log(4) \\ dst.[/tex]

[tex]a log(a) = 1 \\ 4 log(4) = 1 \\dst.[/tex]
Semoga dapat dipahami