Diketahui fungsi f(x) = x^2 - 2x. Tentukan rumus fungsi f(x+2)

[tex]f(x) = {x}^{2} - 2x \\ f(x + 2) =( {x + 2})^{2} - 2(x + 2) \\ = {x}^{2} + 2x + 2x + 4 - 2x - 4 \\ = {x}^{2} + 2x + 2x - 2x + 4 - 4 \\ = {x}^{2} + 2x[/tex]
Semoga dapat dipahami

f(x+2)=(x+2)^2-2(x+2)
=x^2 + 4x + 4 - 2x - 4
=x^2 + 2x