Dari aritmatika diketahui U4=8 dan U8=16. Suku ke 12 adalah.. Tolong yaa

U4 = a + 3b = 8
U8 = a + 7b = 16
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-4b = -8
b = -8 / -4 = 2 »» a + 6 = 8 »» a = 8 - 6 = 2
U12 = a + 11b = 2 + 11.2 = 2 + 22 = 24

Deret Aritmatika

U4 = 8
U8 = 16
b = (U8 - U4)/(8 - 4)
b = (16 - 8)/4
b = 2

U4 = 8
a + 3b = 8
a = 8 - 3.2
a = 2

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U12 = a + 11b
U12 = 2 + 11.2
U12 = 24 ✔