jika f(x) = 2/3-x. tentukan rumus f^-1(x)

f(x) = 2/(3 - x)
y = 2/(3 - x)
3 - x = 2/y
x = 3 - 2/y
x = (3y - 2)/y

f^-1 (x) = (3x - 2)/x ✔

[tex]f(x) = \frac{2}{3 - x} \\ {f}^{ - 1} (x) = .......... \\ y = \frac{2}{3 - x} \\ y(3 - x) = 2 \\ 3y - xy = 2 \\ - xy = 2 - 3y \\ - x = \frac{2 - 3y}{y} \\ x = \frac{ - 2 + 3y}{y} \\ {f}^{ - 1} (x) = \frac{ - 2 + 3x}{x}[/tex]

Maaf kalo salah, semoga membantu