penyelesaian dari 2y+4/4-4y-1/3=1adalah....

[tex] \frac{2y + 4}{4} - \frac{4y - 1}{3} = 1 \\ \frac{6y + 12}{12} - \frac{16y - 4}{12} = 1 \\ \frac{ - 10y + 16}{12} = 1 \\ - 10y + 16 = 12 \\ - 10y = 12 - 16 \\ - 10y = - 4 \\ y = \frac{ - 4}{ - 10} = \frac{4}{10} = \frac{2}{5} [/tex]