Matematika

Pertanyaan

tolong yang dilingkari jawaban beserta caranya
tolong yang dilingkari jawaban beserta caranya

1 Jawaban

  • 1) 3x + 5y + 20 = 0
    5y = - 3x - 20
    m = -3/5
    gradien tegak lurus
    m1 . m2 = - 1
    - 3/5 . m2 = - 1
    m2 = 5/3 ( D)

    2) m = ( y2 - y1 ) / ( x2 - x1 )
    m = ( 7 - 1 ) / ( 4 - 2)
    m = 6 / 2
    m = 3 ( D)

    3) m = ( y2 - y1) / ( x2 - x1)
    m = ( 6 - 1) / ( 3 - 2)
    m = 5 / 1
    m = 5
    gradien sejajar m1 = m2 = 5
    y - 5x + 12 = 0
    y = 5x - 12
    m = 5/1
    m = 5
    jadi yg sejajar garis (i) ( A)

    4) 2x - 3y = 18
    x + 4y = - 2 |×2
    maka
    2x - 3y = 18
    2x + 8y = - 4
    -------------------(-)
    - 11y = 22
    y = - 2
    subtitusi ke pers
    x + 4y = - 2
    x + 4(-2) = - 2
    x - 8 = - 2
    x = - 2 + 8
    x = 6
    nilai x + y
    = 6 - 2
    = 4 ( C )