Metode aliminasi 2. 3x + 2y = 23 x + 6y = 11 3. s - t = 0 6s - t = -12 4. x -2y = -9 2x - y = -12
Matematika
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Pertanyaan
Metode aliminasi
2. 3x + 2y = 23
x + 6y = 11
3. s - t = 0
6s - t = -12
4. x -2y = -9
2x - y = -12
2. 3x + 2y = 23
x + 6y = 11
3. s - t = 0
6s - t = -12
4. x -2y = -9
2x - y = -12
1 Jawaban
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1. Jawaban MraflyH008
2.) 3x+2y=23
X+6y=11
Metofe eliminasi
×1 |3x+2y=23
×3 |3x+18y=33 dikurang (-)
-16y=-10
Y=-10÷(-16)=0,63
Y=0,63 x+6y=11
X+6(0,63)=11
X+3,78=11
X=11-3,78=7,22
3.)s-t=0
6s-t=-12 dikurang(-)
-5s=12
S=12÷(-5)=2,4
S=2,4 s-t=0
2,4-t=0
-t=0-2,4
t=2,4
4.x-2y=-9
2x-y=-12
Metode eliminasi
×2 |2x-4y=-18
×1 |2x-y=-12 dikurang (-)
-3y=-6
Y=-6÷(-3)=2
Y=2 2x-y=-12
2x-2=-12
2x=-12+2
2x=-10
X=-10÷2=-5
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