suatu fungsi dirumuskan f(x) = ax + b. jika f(-2) = 14 dan f(3) = -1 maka nilai f(4) adalah...

f(x) = ax + b
f(-2) = a.-2 + b = -2a+b = 14
f(3) = a.3 + b = 3a + b = -1
-eliminasi
-2a+b = 14
3a +b = -1
---------------- -
1a = 15
a = 15

b = 3a + b = -1
= 3.15 + b =-1
= 45 + b = -1
= b = -1-45 = -46

f(4) = a.4 + b =?
= 15.4 -46 = ?
= 60-46 = 14

Likenya + jawaban terbaik :) makasi

f(x)=ax+b
f(-2)=a(-2)+b
14=-2a+b......(1)

f(3)=a(3)+b
-1=3a+b.......(2)
eliminasi pers(1) dan (2)
-2a+b=14
3a+b=-1
________ —
-5a=15
a=15/-5
a=-3
di substitusikan ke pers(1)
-2(-3)+b=14
6+b=14
b=14-6
b=8
jadi,f(4)=-3(4)+8
f(4)=-12+8
f(4)=-4