Tolong kerjakan nomor 8 beserta caranya, thanks.

f(x) = ²log (6 - x) + ²log (x + 2)
f(x) = ²log (6 - x)(x + 2)
f(x) = ²log (-x² + 4x + 12)

Makasimum saat turunan (-x² + 4x + 12) = 0
-2x + 4 = 0
x = 2

Nilai maksimum :
f(2) = ²log (-2² + 4.2 + 12)
f(2) = ²log 16
f(2) = ²log 2⁴
f(2) = 4 ✔