Tentukan persamaan garis yang melalui titik (-2,8) dan (4,7)

m=y2-y1/x2-x1
m=7-8/4-(-2)
=-1/6
m=-1/6

y-y1=m(x-x1)
y-8=-1/6(x-(-2))
y-8=-1/6x-2/6
y=-1/6x-2/6+8
y=-1/6x-50/6

Rumusnya = y-y¹ x-x¹
------- = -------
y²-y¹ x¹-x²

y-8 x-(-2)
------- = --------
7-8 4-(-2)

y-8 x+2
------- = --------- perkalian silang
-1 6

@ 6 ( y-8) = -1 ( x+2)
@ 6y - 48 = -x - 2
@ 6y = -x -2+48
@6y = -x +46 ....... ( y = mx + c)
x + 6y = 46 ....... ( ax + by = c)
x + 6y - 46 = 0 ........ (ax + by + c = 0)
Nah itulah jawabannya