no 3 dan no 5 tolong kak besok di kumpul

[tex]RS = \sqrt{PR^{2} -PS^{2}} = \sqrt{15^{2} -9^{2}} = \sqrt{225 - 81} = \sqrt{144} = 12 cm SQ = \sqrt{ QR^{2}-RS^{2}} = \sqrt{13^{2} -12^{2}} = \sqrt{169 - 144} =\sqrt{25}=5cm luas = (PS + SQ).RS/2 = 14.12/2 = 84 cm^{2} [/tex]

[tex]p = 3l luas = p.l = 3l.l = 3l^{2} 120 = 3l^{2} 40 = l^{2} l = 2 \sqrt{10} cm p = 3.l = 6\sqrt{10} cm diagonal = \sqrt{2 \sqrt{10}^{2}+6\sqrt{10}^{2} } = \sqrt{40 + 360} = \sqrt{400} = 20 cm [/tex]