Tentukan penyelesaian dari persamaan persamaan berikut! A. ( 6x - 4 ) ( 2x - 1 ) = 4x ( 3x -4 ) +20 B. 2/3 (2x + 3 ) - 1/5 (6x - 5) = 8/15 C. 2x+7/5 - x-3/2 = 3

A.
(6x-4)(2x-1)=4x(3x-4)+20
12x²-6x-8x+4=12x²-16x+20
12x²-14x+4=12x²-16x+20
12x²-12x²-14x+16x=20-4
2x=16
x=16/2
x=8
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B.
[tex] \frac{2}{3} (2x + 3) - \frac{1}{5} (6x - 5) = \frac{8}{15} \: (dikalikan \: 15) \\ 15 \times \frac{2}{3} (2x + 3) - 15 \times \frac{1}{5} (6x - 5) = \frac{8}{15} \times 15 \\ 10(2x + 3) - 3(6x - 5) = 8 \\ 20 x + 30 - 18x + 15 = 8 \\ 20x - 18x = 8 - 30 - 15 \\ 2x = - 37 \\ x = - 37 \div 2 \\ x = - 18.5[/tex]
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C.
[tex] \frac{2x + 7}{5} - \frac{x - 3}{2} = \frac{3(x + 1)}{10} \: kalikan10 \\ 10( \frac{2x + 7}{5} ) - 10( \frac{x - 3}{2} ) = 10( \frac{3(x + 1)}{10} \\ 2(2x + 7) - 5(x - 3) = 3(x + 1) \\ 4x + 14 - 5x + 15 = 3x + 3 \\ 4x - 5x - 3x = 3 - 14 - 15 \\ - 4x = - 26 \\ x = - 26 \div - 4 \\ x = 6.5[/tex]
Sambil dicek lagi ya :)