bayang titik s (3,-2) oleh dilatasi [0,4] kemudian dicerminkan terhadap garis y = -X adalah

jawab


S =(3, 2)
D[O, 4] → S' = { 4(3) , 4(2)}
S' = (12, 8) di cerminkan y = -x
S" = (-8, - 12)

atau dengan matriks
T1 = Matriks dilatasi
T2 = matriks Refleksi

T2 o T1 (x,y) = (x' , y')

[tex] \left[\begin{array}{ccc}0&-1\\-1&0\end{array}\right]\,\left[\begin{array}{ccc}4&0\\0&4\end{array}\right]\,\left[\begin{array}{ccc}x\\y\end{array}\right]\,=\left[\begin{array}{ccc}x'\\y'\end{array}\right] [/tex]

[tex]\left[\begin{array}{ccc} 0&-4\\-4&0\end{array}\right]\,\left[\begin{array}{ccc}x\\y\end{array}\right]\,=\left[\begin{array}{ccc}x'\\y'\end{array}\right] [/tex]

[tex] \left[\begin{array}{ccc}0&-4\\-4&0\end{array}\right]\,\left[\begin{array}{ccc}3\\2\end{array}\right]\,=\left[\begin{array}{ccc}x'\\y'\end{array}\right] [/tex]

x'= - 8
y'  = - 12