1.) 19-3y<2-5(y+1) 2.) tentukan nilai a dari 3(2a-1)+1=-2(2a+9) Tolongbantuyaa

1. 19 - 3y < 2 - 5 (y + 1)
--> 19 - 3y < 2 - 5y -5
19 - 3y < -5y -3
5y - 3y < -19 - 3
2y < -22
y < -11

2. 3 (2a - 1) + 1 = 2 (2a + 9)
--> 6a - 3 + 1 = 4a + 18
6a - 2 = 4a + 18
6a - 4a = 18 + 2
2a = 20
a = 10

1. 19 - 3y < 2 - 5 (y + 1)
19 - 3y < 2 - 5y - 5
-3y + 5y < 2 - 5 - 19
2y < -22
y < -11

2. 3 (2a - 1) + 1 = -2 (2a + 9)
6a - 3 + 1 = -4a - 18
6a + 4a = -18 + 3 - 1
10a = -16
a = -8/5