diferensiasi (2√x cos (x)) tolong jawaban dan penjelasannya yaa :)

jawab

y = (2√x) . cos (x)

y = 2x^(1/2) . cos (x)

u = 2x^(1/2)
du  =  x^(-1/2) = 1/√x

v = cos x
dv = - sin x 

y = u v
y' = u'v + uv '

y' = 1/√x . cos x + 2√x . (-sin x)
y' =  1/x  √x . cos x - 2√x sin x
y' = 1/x  √x ( cos x - 2x sin x )