jabarkan aljabar dibawah jni dengam hukum distrubutif a (3x+10)(2x+2) b (5x+4y) (2x-y) c (10x-12) (2x+3)

a. (3x+10) (2x+2)
= 6x^2 +6x +20+20
=6x^2+6x+40

b. ( 5x+4y) (2x-y)
=10×^2 +5xy+8xy+4y^2
= 10x^2 + 13xy+4y^2

c. (10x-12) (2x+3)
= 20x^2+30x-24x-36
= 20x^2+6x-36