Matematika

Pertanyaan

^4log(4x-3)≤1+^16(x-3/4)

1 Jawaban

  • ⁴log (4x - 3) ≤ 1 + ¹⁶log (x - ¾)
    ⁴log (4x - 3) ≤ ⁴log 4 + ⁴log (x - ¾)^{½}
    (4x - 3) ≤ 4√(x - ¾)
    (4x - 3)² ≤ 16(x - ¾)
    16x² - 24x + 9 ≤ 16x - 12
    16x² - 40x + 21 ≤ 0
    (4x - 7)(4x - 3) ≤ 0
    Didapat ¾ ≤ x ≤ ⁷/₄ ... (i)

    Syarat :
    4x - 3 > 0
    4x > 3
    x > ¾ ... (ii)

    x - ¾ > 0
    x > ¾ ... (iii)

    HP : {x | ¾ < x ≤ ⁷/₄ , x ∈ R}



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