^4log(4x-3)≤1+^16(x-3/4)
Matematika
ibuud
Pertanyaan
^4log(4x-3)≤1+^16(x-3/4)
1 Jawaban
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1. Jawaban AnugerahRamot
⁴log (4x - 3) ≤ 1 + ¹⁶log (x - ¾)
⁴log (4x - 3) ≤ ⁴log 4 + ⁴log (x - ¾)^{½}
(4x - 3) ≤ 4√(x - ¾)
(4x - 3)² ≤ 16(x - ¾)
16x² - 24x + 9 ≤ 16x - 12
16x² - 40x + 21 ≤ 0
(4x - 7)(4x - 3) ≤ 0
Didapat ¾ ≤ x ≤ ⁷/₄ ... (i)
Syarat :
4x - 3 > 0
4x > 3
x > ¾ ... (ii)
x - ¾ > 0
x > ¾ ... (iii)
HP : {x | ¾ < x ≤ ⁷/₄ , x ∈ R}