Penyelesaian dari 2 per 3(2y-3)=1 per2 (4y+2) =

[tex] \frac{2}{3} (2y - 3) = \frac{1}{2} (4y + 2) \\ \frac{4y - 6}{3} = \frac{4y + 2}{2} \\ 8y - 12 = 12y + 6 \\ 8y - 12y = 6 + 12 \\ - 4y = 18 \\ y = \frac{18}{4} \\ y = 4 \frac{2}{16} [/tex]

semoga membantu