himpunan penyelesaian dariv|2x-1|=|4x+3| adalah

|2x - 1| = |4x + 3|
2x - 1 = 4x + 3
2x - 4x = 3 + 1
-2x = 4
x = 4/-2
x = -2

2x - 1 = -(4x + 3)
2x - 1 = -4x - 3
2x + 4x = -3 + 1
6x = -2
x = -2/6 (sama sama dibagi 2)
x = -1/3

x = { -2, -1/3 }

Semog membantu
*Mohon pilih sebagai jawaban tercerdas ya. Trims

¦2x-1¦=¦4x+3¦
pakai sifat
¦x¦=¦y¦
=>x^2=y^2
(2x-1)^2=(4x+3)^2
=>(2x-1)(2x-1)=(4x+3)(4x+3)
=>4x^2-2x-2x+1=16x^2+12x+12x+9
=>4x^2-4x+1=16^2+24x+9
=>4x^2-16x^2-4x-24x+1-9=0
=>-12x^2-28x-8=0 bagi -4
=>3x^2+7x+2=0
=>(3x+6)(3x+1)
=>3x+6=0
3x=-6
x=-6/3=-2
=>3x+1=0
3x=-1
x=-1/3

trima kasih