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No. 2
METODE SUBSTITUSI

3x+2y-4 = 0 3x+2y=4 ... (1)

x-3y-5 = 0 x = 3y+5 ... (2)

maka, 3x+2y = 4
=3(3y+5) + 2y = 4
=9y+15+2y = 4
=11y = 4 - 15
=11y = -11
= y = -1

subsitusikan y= -1 ke pers 1
3x+2y = 4
3x+2(-1)= 4
3x-2 = 4
3x = 4+2
3x = 6
x = 2

jadi (x,y) = (2,-1)

nb: no3 penyelesaiannya sama seperti no2