Tentukan titik potong kurva f(x)=x^ dan f(x) = 9x-8

titik potong
y = y
x² = 9x - 8
x² - 9x + 8 = 0
(x - 1)(x - 8) = 0
x = 1 atau x = 8

x = 1
y = 9x - 8 = 9.1 - 8 = 1
(1,1)

x = 8
y = 9.8 - 8 = 64
(8,64)

Titik potong :
(1,1) dan (8,64)