Tentukan bentuk sederhana 3ab per 2c di bagi x-3 per 3y Tlng bantu

[tex] \frac{3ab}{2c} \div \frac{x - 3}{3y} \\ = \frac{3ab}{2c} \times \frac{3y}{x - 3} \\ = \frac{(3ab)(3y)}{(2c)(x - 3)} \\ = \frac{9aby}{2cx - 6c} \\ = \frac{9aby}{2(cx - y)} [/tex]