4log(x²-6-4) = 4 log (2x²-12)

4 log (x²-10)-4 log (2x²-12) = -X² + 2

⁴log (x² - 6x - 4) = ⁴log (2x² - 12)
2x² - 12 = x² - 6x - 4
2x² - x² + 6x + 4 - 12 = 0
x² + 6x - 8 = 0
a = 1
b = 6
c = -8

rumus abc
x1.2 = (-b ± √(b² - 4ac))/2a
x1.2 = (-6 ± 2√17)/2
x1.2 = -3 ± √17

syarat numerus > 0

Nilai x yg memenuhi :
x = -3 - √17