Jika 3^×+1 + 6(3^×-2)=3^×+8,maka nilai 4x^2-1

jawab

3ˣ⁺¹  + 6. 3ˣ⁻²  = 3ˣ + 8

3. 3ˣ +  6. 3⁻². 3ˣ = 3ˣ + 8
a = 3ˣ
3a  + 6/9  a = a + 8
3a +6/9 a - a =  8
8/3 a  = 8
a = 8 (3/8)
a = 3
3ˣ = 3 → x = 1

nilai  4x² - 1 = 4(1)² - 1
= 4 - 1
= 3


4/