benda bermassa 300 gram bergerak melingkar dengan kelajuan 5m/s . jari jari lintasan gerak benda tersebut 100 cm .percepatan sentripetal benda sebesar

Mapel : Fisika
Materi : Gerak Melingkar Beraturan
Kelas : X
Kata kunci : percepatan sentripretal
Kode Kategori : 10.6.5
KTSP
Pembahasan :


* Diketahui
m = 300 gram = 0,3 kg
V = 5 m/s
R = 100 cm = 1 meter

* Ditanya
as = __?

* Jawab

as = V²/R
as = 5²/1
as = 25 m/s². ←

Jadi, percepatan sentripretal benda sebesar 25 m/s².


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m = 300 gram = 0,3 kg
v = 5 m/s
r = 100 cm = 1 m
as?

penyelesaian:
as = v² / r

as = 5² / 1

as = 25 m/s²