bantuin saya dong, nanti siang dikumpul soalnya

jawab

(1)
a. ∫6x (2x+ 1) dx
= ∫ 12x² + 6x dx
=  4x³ + 3x² +c

b. ∫ (x +2)(x - 3) dx
= ∫ (x² - x  - 6 ) dx
= 1/3 x³  - 1/2 x²  - 6x + c

(2)
a. ₂⁻¹∫ (x - 1)² dx
= ₂⁻¹∫ (x²- 2x + 1) dx
= [ 1/3 x³ - x² + x]⁻¹₂
= 1/3(-1-8) - (-1- 4) + (-1- 2)
= -9/3 - 5 - 3
= -3 + 5 - 3
=  - 1

b) ₁³∫ (4x³ + 2x - 4) dx
= [ x⁴ + x² - 4x]³₁
= (81-1) + (9-1) - 4(3-1)
= 80 + 9 - 8
= 81