1. gambarlah grafik dari persamaan garis 3y-4x+12=0 2. persamaan garis yg melalui titik (5,-6)dan tegak lurus dgn garis 3y-5x+12=0 3.persamaan garis yg melalui

2) 3y - 5x + 12 = 0
3y = 5x - 12
m = 5/3
gradien saling tegak lurus
m1 . m2 = - 1
5/3 . m2 = - 1
m2 = - 3/5
pers garis
y - y1 = m ( x - x1 )
y + 6 = - 3/5 ( x - 5)
y = - 3/5 x + 3 - 6
y = - 3/5 x - 3 ( dikali 5)
5y = - 3x - 15
5y + 3x + 15 = 0


3) m = ( y2 - y1 ) / ( x - x1 )
m = ( - 6 + 7 ) / ( 8 - 3)
m = 1 / 5
gradien saling sejajar
m1 = m2 = ¹/5
pers garis
y - y1 = m ( x - x1 )
y - 3 = 1/5 ( x + 6 )
y = 1/5 x + 6/5 + 3 ( dikali 5)
5y = x + 6 + 15
5y - x = 21